$x\left(10x\right)$
$\sqrt{\frac{24}{12}}$
$\left(\sqrt{7x}^3\right)^3-3\left(\sqrt{7x}^3\right)^2.\left(4x^2y^2\right)+3\left(\sqrt{7x^3}\right).\left(4x^2y^2\right)^2-\left(4x^2y^2\right)^3$
$\left(-40\right):5:2$
$\left(x^{\frac{1}{3}}+y^{\frac{1}{3}}\right)^5$
$2+x=x+2$
$0\ge x^2+x-2$
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