$\left(m^3+4m^2+5m+2\right)\left(m-2\right)$
$6d+3d-2$
$y'+\frac{1}{6}y=e^{-2x}+8$
$\left(3x-\frac{3}{4}\right)^2$
$\frac{-x^4-4x^3+6x^2-7}{x^2-2}$
$3u^2-8u-3=0$
$prove\:cos^2\theta\:-2sin^2\theta\:=3cos^2\theta\:-2$
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