$\frac{11a^3-3a^5-46a^2+32}{8-3a^2-6a}$
$\left(6p^2q+10p^3q^2\right)\left(6p^2q-10p^3q^2\right)$
$\frac{x^2+3x+4}{2x+2}$
$8+-1+10$
$w^{-4}\:w^0$
$3x-6>2x-12$
$\:\left(m-\frac{5}{4}\right)^3$
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