$\frac{7x-4}{3}\ge2$
$144x^2-72x+36$
$-\sin\left(x\right)\sin\left(x^2\right)+\cos\left(x\right)\cos\left(x^2\right)$
$\int\frac{x+3}{x\left(1+x^2\right)}dx$
$-10:\left(-3-2\right)-\left(-5-3-\left(+5\right)\right)$
$7+6.3$
$x^2-2x-63=0$
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