$\frac{3}{4}x-1=\frac{4-3x}{-4}$
$9m^3-27m$
$x ^ { 5 } - 3 x ^ { 4 } + 4 x ^ { 2 }$
$x+3\le41$
$\left(120a\:120b\:120c\right)\:-\:\left(30a\:\:90b\:60c\:\right)$
$49k^2\:-\:56k\:+\:16$
$\:-\frac{3}{4}a^2b-\frac{1}{8}a^2b$
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