$x^2-10x+19=0$
$2\left(x\:-2\right)\:+\:3\left(x\:-\:2\right)\:$
$-3x+5\ge-1$
$x-8=6$
$\left(\frac{\sin\:\left(x\right)\cos\:\left(x\right)+\cos\:\left(x\right)}{1+\sin\:\left(x\right)}\right)^2$
$\int\left(\frac{4}{3}x^3+\frac{7}{4}x^5-\frac{2}{9x}\right)dx$
$5x-2<-7x$
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