$\frac{-3x+4}{2}>-5$
$\left(2x-9\right)\left(7x-1\right)$
$\frac{3x^{\frac{-1}{2}}}{2x}$
$3x^2-10x+7=0$
$8\sqrt{20}+3\sqrt{45}$
$\left(3x\:-\:2^2\right)$
$\left(-2\right)^2+3\left(-2\right)$
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