$sin2x\:=\frac{1}{2}$
$-260wx+169wx^{2}$
$\lim_{x\to3}\left(-2x-3\right)$
$\left(t^2+9\right)\frac{dx}{dt}=\left(x^2+4\right)$
$\int28xe^{-2x}dx$
$b^2+8b+25$
$\int\frac{e^{\frac{1}{2}}}{x^3}\:dx$
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