$\frac{dy}{dx}=\frac{y}{2x\:+\:2y}$
$640-10x^2$
$cos\left(3x+4x\right)$
$-13q\:+\:7\left(10q\:+\:15\right)\:=\:-7\:+\:q$
$f\left(x\right)=\frac{x^2+9x}{1-cos3x}$
$3x+2>\frac{1}{3}-x$
$\int\left(\frac{x^2+3}{4}\right)dx$
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