$\lim_{x\to-3}\left(\frac{\left(4x+12\right)}{x+3}\right)$
$\left(a+9\right)^2=a^2+y\:a+81$
$x^2+x+2x-5+3x^2+7$
$\lim_{x\to0}\left(\frac{1}{cosx-1}\right)$
$\lim_{x\to1}\left(4-4x\right)$
$7+5v-1+4v-10a+1$
$\frac{d}{dx}y=3$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!