$x^2+4x=13$
$\int\frac{\left(x-2\right)}{\left(x^2-6x+5\right)}dx$
$\int\frac{x^3+x+3}{x^2+2x+1}dx$
$2x-1\ge27+6x$
$-3\cdot x=18$
$\tan^2x\csc^2x-3=0$
$4x^2+8x-5$
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