$\left(6x\right)^2-2\left(6x\right)+\left(y^2\right)^2$
$\frac{dy}{dx}=\frac{1+x}{y}$
$5x+3y,\:x=0,\:y=0$
$\:+4\:-\:7\:-8\:$
$19.3\left(1.089\right)^{6.6}$
$5x^2+4x+3-3x+2x^3-7x^2+6x$
$\int_{-5}^{-3}\left(-\frac{1}{3x-2}\right)dx$
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