$\left(7a^2-6\right)\left(3a-2b\right)$
$\tan=\frac{1}{6}$
$\frac{x^2-9}{x+3}$
$\left(x^2-4\:\:\:\right)^2$
$\frac{26.2}{6.2}$
$\frac{4}{9x}-\frac{3x}{7}$
$2x^2=-7x-29$
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