$\sqrt{6m}\cdot\sqrt{18m^2}$
$\left(3x^2-2\right)\left(3x^2+3\right)$
$\frac{1}{tan\left(x\right)cos\left(-x\right)}$
$-28v^2-8v-36$
$108-\left(-7\right)$
$2-3+34$
$\int\frac{x-9}{x^2-\:6x}dx$
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