$4x^2-4x^3y^3=3$
$g^2=49$
$\frac{dy}{dx}=\frac{1+4y^2}{2x^2+2}$
$\int\left(\frac{a}{4x+3}\right)dx$
$-\frac{4}{5}x=12$
$6x-10=-16$
$\int_{-\infty}^3e^{x-3}dx$
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