$\frac{1}{4}\left(24x+8\right)$
$6\left(-\frac{3}{2}\right)+4\left(-\frac{3}{2}\right)+3$
$4xy^2+8\cdot2xy^1-xy$
$\tan x\:\sec x\:\sin x=\tan^2x$
$\sqrt{40a^3}b^2-a\sqrt{90ab^2}$
$log\left(tan^2x\right)=log\left(\frac{1}{100}\right)$
$36a^6-64b^2$
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