$\int\frac{1}{\left(16x-x^3\right)}dx$
$\int8\cdot\cos\left(x\right)dx$
$\left(6a+4b-8c\right)^2$
$-3\:x\:5\:+\:7$
$\frac{189}{8.5}$
$-\left(-4n^7a^8b^7\right)^3$
$\int\left(\frac{p}{2}\right)dp$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!