$6x^2+13x-8$
$16y^2+64y+4$
$\frac{\left(w^4\right)}{w^8}^2$
$\frac{3x+6}{3}$
$\left(4m^2-a^3\right)^2$
$\sqrt[5]{x^{12}}\sqrt[5]{y^9}\sqrt[5]{z^5}\sqrt[5]{w^3}$
$2x-9>1$
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