$\frac{x-3}{2}-\frac{1}{3}x>\frac{11}{3}$

$\frac{\cos\left(b\right)}{\cot\left(b\right)}=\sin\left(b\right)$

$\left(xy^{2}z+1\right)z^{2}$

$\int\frac{1+6x}{x^3+8x^2+16x}dx$

$\lim_{x\to0}\left(\frac{\left(1-cosx\right)}{x^3}\right)$

$x-3=25$

$\left(x+2\right)^2\left(2x^2+8x+7\right)$