$\frac{64a^6-729b^6}{2a+3b}$
$5+6+5\cdot6$
$-7cosx=-2cos^2x-3$
$\lim_{x\to3}\left(\ln\left(\frac{x}{3-x}\right)\right)$
$2x\:+\:5x\:<x\:+\:1$
$\int\left(5x^4-3x^2\right)\left(4x^5-4x^3\right)^6dx$
$\lim_{x\to\infty}\left(1+\frac{2}{3x}\right)^{6x}$
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