$16+72+8+32+56\cdot8$
$\frac{1}{x^3}-\frac{2}{x^2}$
$\lim_{x\to\infty}\left(\frac{e^x-1}{\sin\left(4x\right)}\right)$
$\frac{1}{\left(n+1\right)\left(n+2\right)\left(n+3\right)}$
$\frac{2^2-\left(-12\right)}{8}$
$\left(4+3y\right)^3$
$\sqrt{2^2}-2\cdot2$
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