$x^2=6-x$
$\frac{1+tan^2x}{sec^2x}$
$\frac{x^2+2x+4}{x^2}$
$\tan^4x\sec^3x$
$\left(1-e^{-x}\right)^4$
$-a^2-10a+25$
$\int\left(x^5+x^2\right)^8\left(5x^4+2x\right)dx$
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