$+\left(-3-5+6\right)-\left(+7-3+6\right)-5$
$\int_1^4\left(\frac{x^2}{x^2+4}\right)dx$
$\int\left(x\left(x-20\right)^5\right)dx$
$-21.\:-5$
$8+4-3+2-5$
$\left(-10\right)-\left(-2\right)$
$x^2+15x+3=0$
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