$\sqrt{3}\cot\left(\frac{1}{5}x\right)+1=0$

$\frac{22x^{16}y^8}{6x^4y^2}$

$\left(18-3\left(5\right)\right)\left(1-1\right)$

$n^2<4n-3$

$2x-12=x+15$

$2+2\sqrt{2}\left(\infty\right)$

$\frac{1}{v}+\frac{\left(3v+12\right)}{\left(v^2-5v\right)}=\frac{\left(7v-56\right)}{\left(v^2-5v\right)}$