$\int_1^{\infty\:}\frac{x^5}{\left(1+x^3\right)^{\frac{7}{4}}}\:dx$
$\frac{dy}{dx}=\frac{y\left(x-1\right)^2}{y+3}$
$\left(6a-4b\right)$
$4\left(y-2\right)+5\left(y+3\right)=-29$
$12-\frac{-10}{2}$
$\int_0^9\sqrt{x}+3dx$
$-25x=75$
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