$x^2+4x>4$
$\frac{1}{5}\int_8^{\infty}\left(e\frac{-t}{5}\right)dt$
$4y-6$
$\left(5\right)^2\cdot\left(-3\right)^2$
$10+27d+7-d$
$-\left(-380-150-230\right)-\left(-1500-1200+2700\right)$
$\frac{1-\sin\left(x\right)}{\sin\left(x\right)}=\frac{1}{\sin\left(x\right)}$
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