$y'\:=\:2xy\:+\:x$
$\sqrt[7]{128a^{14}b^2}$
$9x^2-y^2=1$
$\left(\frac{4}{5}x^2+4x^{\frac{2}{3}}\right)\left(\frac{4}{5}x^2-4x^{\frac{2}{3}}\right)$
$25^2+36$
$2^2+-1^3$
$\left(2a^3+5a-3\right)-\left(2a^3+3a^2-4a\right)$
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