$\:y'=\left(y-5\right)e^{-3x+5}$
$\left(4y^3+15\right)\left(4x^3+15\right)$
$\left(x^{4a-5}\right)\left(x^{4a-5}\right)$
$cos\left(x\right)\cdot tan\left(-x\right)$
$\left(2q-5b\right)^2$
$-x+2\ge0$
$\left(8m^{-3}\:n^9\right)^0$
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