$2\left(10x^3\right)\left(9xy^5\right)$
$5a-245$
$3\left(10+2b\right)=24$
$2x\:\le\:2\:\left(x-1\right)$
$\frac{x^3-7x-6}{x-3}$
$\left(3x^2-2x-8\right)+\left(6x^2-5x\right)$
$\int_2^5\left(4x^3-3x^2\right)dx$
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