$\arctan\left(2.4\right)$
$\frac{1-cos^2x+sin2x-sin^2x}{1+cos2x}=\tan\left(x\right)$
$5a^3\:-\:2a^2x\:-\:5ax^2\:+\:2x^3\:\cdot$
$-\left[\left(-5\right).\left(-3\right)-\left(-10\right):\:\left(+2\right).\left(-4\right)\right]$
$\lim_{x\to\infty}\left(\frac{x^2+5}{3^x}\right)$
$\lim_{x\to\infty}\left(8-10x\right)$
$\left(\frac{2x}{3\left(\left(2x-3\right)-3\right)}\right)$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!