$\left(-2x-y\right)^4$
$-4x-5y=-32$
$3-2\left(x+1\right)>3x+6$
$5xy-y=9x+4y$
$\:-\:3gh\:-\:\left(8gh\right)\:$
$\frac{\left(x^5+2x^4-kx^2+x\right)}{\left(x+2\right)}$
$\int_0^{\frac{\pi}{8}}\left(\sec^2\left(x\right)\right)dx$
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