$( a ^ { 3 } + 7 ) ( a ^ { 3 } - 6 )$
$\sec^22x-1=\tan^22x$
$-6+\left(5-9+2-3+4\right)-7-\left(-9+2+4+1\right)$
$1\frac{2}{x+1}=\frac{3}{x-1}$
$\left(-4x^2y^3\right)^4$
$8.16+2.25+15.321$
$\frac{xy\sqrt[3]{y^2}}{2}$
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