$y-4=0$
$tan^2\left(x\right)\:csc^{2\:}\left(x\right)\:=\:\frac{1}{cot^2\left(x\right)}-1$
$\frac{x^2-4x-12}{x-2}$
$9\:.\:\left(-\:1\right)\:-\:2$
$45-\left(-27\right)$
$\left(\:x\:+\:5\right)\:\left(x\:-\:8\right)\:=\:0$
$2\left(a+b\right)$
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