$-14n^2m^3\left(2h^2m^2-3xy-8m^4\right)$
$1=\left(\left(sin\left(x\right)+cos\left(x\right)\right)\right)^2$
$\left(2x\right)^2-6^2+x^2+2\left(x\right)\left(6\right)+6^2$
$y'=y-2$
$-20ab+11ab$
$\frac{2}{3\:}x+5=9$
$2.44-87.23$
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