$3y^2-4y=5$
$\left(\frac{4a^{4\:}b^3}{2a^2\:b}\right)^3$
$\left(x^2+12-36\right)$
$3+\left(\left(9\cdot2\right)-3\right)\cdot1\left(-2\cdot3\right)$
$\left(\frac{1}{512}\right)^{-x^{4}}$
$8rs^{-\frac{4}{3}}$
$-\left(2x+5\right)\:+\:3x$
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