$4-16x^2$
$\log_{16}x=2$
$ax^2+bx=0$
$8-4\cdot2+\left(6-2^3\right)$
$\int5f^4df$
$\frac{0^3-1}{0^2}$
$\int\frac{4-x}{\sqrt{x^2-1}}dx$
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