$\left(-8ab^4c+2x^3+12x^4y^5\right)$

$x^2-1=8$

$\left(\frac{6}{5}x^{2}-\frac{1}{4}y^{2}\right)\left(\frac{6}{5}x^{2}+\frac{1}{3}y^{2}\right)$

$x-6=18-7x$

$y\:ln\:x\frac{dy}{dx}=\left(\frac{y+1}{x}\right)^2$

$-9+10+4+5+6$

$\left(3a^2b^3\right)\cdot\left(5a^3b^4c^2\right)$