$\frac{125a^3-27b^3}{5a-3b}$
$2x-\frac{9}{x+4}=\:\frac{3x-6}{x+4}$
$xy^2+3y^2=x+y^2$
$\frac{1}{4}t^2-\frac{9}{4}t=1$
$\lim_{x\to2}\left(\frac{x^2-3x+8}{x-1}\right)$
$-3\left(\sqrt{2}x\right)\left(-\sqrt{2}\right)^2$
$9x\:+\:5\:=\:-13$
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