$z^2-6z+9=0$
$\frac{dy}{dx}\left(2x^4-4xy+\sin\left(2y\right)=5x\right)$
$\left(x\right)=\frac{x^2-6x+10}{x-1}$
$\frac{7.895}{34}$
$4x+7=x+16$
$5+2x=5x-7$
$-6\cdot\left(12c\right)$
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