$m+4^2$
$3\frac{-8}{-3}$
$\left(x-12\right)\left(x+4\right)=9$
$12\cdot7$
$35+4\cdot$
$2\sin\left(x\right)+1=-\cos\left(2x\right)$
$\left|-6-\left(-2+4\right)-5\right|-\left|-8-\left(7-2\right)-6\right|$
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