$4n^2\cdot6n^3$
$v^2+6v-7$
$5d+80d-40$
$\sqrt[3]{z^2}$
$\frac{d^4}{dx^4}\tan\left(x\right)$
$7\frac{dy}{dx}=\frac{1}{\left(-10y-14\right)^{-1}}$
$x^4-2^2$
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