$\left(36x^4+12x^5-6x^3\right)$

$-7+4^2$

$\int2f^3\left(f^4-3\right)df$

$\frac{\sin\left(x\right)}{\cot\left(x\right)}=\frac{1}{\tan\left(x\right)}+\frac{1}{\cot\left(x\right)}$

$\lim_{x\to0}\left(\frac{1+x^2}{e^{2x}}\right)$

$x-\sqrt{x-1}=1$

$\int\frac{x}{\sqrt{28+12x-x^2}}dx$