$x^2\:\left(x-4\right)^2$
$9u=8n+7u$
$\left(2+3m^2\right)^2$
$2xy-3x=0$
$\lim_{x\to\infty}\left(1+3x\right)^{\frac{x}{2}}$
$4t^2+39=0$
$\left(7t^2+6t-1\right)-\left(3t-5t^2+4-t^3\right)$
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