$5a^2+2bc+3d=10$
$\lim_{x\to02}\left(\frac{\tan^2\left(x-2\right)}{x^2-4}\right)$
$a^2-2a-24$
$3y^3dx=6x^2dy$
$5x+13=10x-12$
$b^2+1a-6$
$\left(2m+15\right)\left(-m-3\right)$
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