$8^{x^2-2x}=\frac{1}{2}$
$\int_{e^2}^{\infty}\frac{9\ln\left(x\right)}{x}dx$
$\frac{d^2u}{dx^2}=6xe^{-t}$
$b^2+26b+91$
$\int\left(\frac{x^2+2x+4}{x}\right)dx$
$\int 8 x ^ { 20 } d x$
$4x+1=3x+3$
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