$\lim_{x\to\infty}\left(\frac{6x+9}{2x^2-2x+8}\right)$
$\lim_{x\to0}\left(cos\left(5x\right)^{\frac{2}{x^2}}\right)$
$x^2+8x-9>1$
$4x^2-4x-35=0$
$2\cos\left(2x\right)-1=cos\left(4x\right)+cos\left(2x\right)$
$\frac{d}{dx}\:\sqrt{5+2e^{7x}}$
$4x^2\:+\:9x\:-\:2x\:+\:x\:-\:5$
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