$\left(x-3\right)^2>2$
$\left(a+7\right)\left(a-5\right)$
$\lim_{x\to0}\left(\frac{\left(sen\left(4z^2\right)+cos\left(2z\right)-e^{-2z}\right)}{ln\left(z^2+1\right)+2z}\right)$
$a=21,b=14,\beta\:=100^\circ\:$
$3\left(g\:+\:5\right)+2g$
$\frac{8x^2+6x-12}{x+4}$
$x^2+2x+1\cdot x+3$
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