$x\cdot\frac{dy}{dx}+1=y$
$\left(27y^2-4y-6\right)-\left(\left(-4y^2+5y-9\right)-\left(-23y^2+16y-8\right)\right)$
$\int\left(\frac{sec^2z}{tanz}\right)dz$
$\int y\sec\left(y\right)dy$
$r^2-30r+225$
$-46-\left(-34\right)$
$\sin^2x-\left(1\cos^2x\right)-\tan x\cdot\csc x$
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