$\int_{-\infty}^6\left(\frac{6}{x^2+4}\right)dx$
$2x-7\le\:12x-5$
$\int\left(2x+1\right)^{\frac{5}{2}}dx$
$1x^2-7x^1+12x^0$
$-5-3-8-7-9-1$
$f\left(x\right)=5x^3+7x$
$8x-10x+x$
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