$\left(2x+3\right)in\:x$
$\lim_{x\to\infty}\left(\ln\left(\frac{x-8}{x}\right)\right)^{\frac{x}{4}}$
$\frac{6}{7}.\frac{6}{10x}$
$\int\frac{x^3+3x^2-2x+7}{4}dx$
$5^0+4^2-2^3$
$\frac{6x-3}{x+2}\le5$
$dy=4xydx$
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